Ok. This has been bothering me for some time so I'm going to throw it to the experts.
If you are familiar with this recent news story:
http://www.twincities.com/crime/ci_2464 ... cities.com
The suspect supposedly shot the victim with what was described in another report (that I can't find at the moment) with a Ruger New Vaquero in .357 magnum. This report (and the others I've read) indicate that the extractor rod was found on the victim's chest. The stories seem to indicate that the suspect was caught taking some ammunition he found at the house he was visiting and that may have led to the altercation that ended in the shooting.
I actually know the suspect (not going to say how) and I know he has an IQ in the single digits. I'm really wondering if he got the gun somewhere but didn't have any ammo for it and when he found the box of ammo in the basement he shoved a few rounds in to see if it would work. When he was confronted, he ended up pulling the trigger on a bullet that fit in the gun, but was perhaps not the right caliber and ended up killing the victim and blowing the gun apart at the same time (thus the extractor left at the scene).
So, my question is...What other caliber(s) would fit in a .357 revolver, fire, kill someone at close range and schmuck up the gun? And I can't imagine if he found the box of ammo at a fellow homie's house it would be a very rare ammo. I haven't tried it, but would a 9 mm (rimless) actually fire from a .357 (rimmed) under the right circumstances?